16.8t^2-6t=0

Solution for 16.8t^2-6t=0 equation:

16.8t^2-6t=0

a = 16.8; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·16.8·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*16.8}=\frac{0}{33.6}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*16.8}=\frac{12}{33.6}
=4/11.2
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